To sum up, consider a system of linear simultaneous equations where all equations are consistent, however, due to the linear dependence between some equations the number of independent equations is less than the number of unknowns. Such a system has infinitely many solutions. To read more about the existence of a unique solution, inconsistency, and linear dependence, please see the recommended books. Index Content Questions. Prev Next. Therefore this system of linear equations has no solution.
As you can see the code gives us an error suggesting there is no solution to the matrix. As you can see, the final row of the row reduced matrix consists of 0. This means that for any value of Z, there will be a unique solution of x and y, therefore this system of linear equations has infinite solutions. As you can see we get a different type of error from this code. It states that the matrix is ill-conditioned and that there is a RuntimeWarning. This means that the computer took to long to find a unique solution so it spat out a random answer.
Add a comment. Active Oldest Votes. Cameron Buie Cameron Buie I've seen better, personally. However, I do feel this is one of my better answers. Just FYI, when commenting on someone's post, it isn't necessary to tag them. If you want to get the attention of another commenter, though, you should tag in most cases. Ben Ben 61 1 1 bronze badge. Sign up or log in Sign up using Google.
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